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David Bernier  
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 More options Oct 31, 9:33 pm
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Sat, 31 Oct 2009 12:33:17 -0400
Local: Sat, Oct 31 2009 9:33 pm
Subject: about computing zeta'(s) in the critical strip
I'm interested in methods for computing the derivative of the
Riemann zeta function, zeta', in the critical strip
0<= Re(s) <= 1.

One of the equivalents of the Riemann Hypothesis is
that zeta' has no zero s with 0 <  Re(s) < 1/2 .

Speiser [1934]:

http://www.aimath.org/WWN/rh/articles/html/89a/

There's a paper by Garaev and Yildirim, available in
it's pre-print form here:
http://arxiv.org/abs/math/0610377v2

"On small distances between ordinates of zeros of zeta(s) and zeta'(s)"
which seems like it could be a good source for previous results
on the zeros of zeta' and how they relate to the zeros of zeta,
in the critical strip.

Or else, maybe someone has already computed some of the zeros
of zeta' in the critical strip, but I didn't find anything like
that.

David Bernier


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Raymond Manzoni  
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 More options Nov 1, 2:28 pm
Newsgroups: sci.math
From: Raymond Manzoni <raym...@free.fr>
Date: Sun, 01 Nov 2009 10:28:53 +0100
Local: Sun, Nov 1 2009 2:28 pm
Subject: Re: about computing zeta'(s) in the critical strip
David Bernier a écrit :

    Two recent papers :

  Haseo Ki(2008) "The zeros of the derivative of the Riemann zeta
function near the critical line" <http://arxiv.org/pdf/math/0701726>

  Yitang Zhang(2001) "On the zeros of zeta'(s) near the critical line"
<http://eduunix.ccut.edu.cn/index2/math/202.38.126.65/mathdoc/Duke.Mat...>

    Some references provided in these papers could be interesting too.
    Hoping it helped a little,
                Raymond


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Marko Amnell  
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 More options Nov 1, 4:00 pm
Newsgroups: sci.math
From: "Marko Amnell" <marko.amn...@kolumbus.fi>
Date: Sun, 1 Nov 2009 13:00:06 +0200
Local: Sun, Nov 1 2009 4:00 pm
Subject: Re: about computing zeta'(s) in the critical strip

Maybe Michael Rubinstein's L-function software will work.
The default L-function is the Riemann zeta function.

http://pmmac03.math.uwaterloo.ca/~mrubinst/L_function_public/L.html

There's an option for computing derivatives about which the Readme file
says:

"Presently the derivative option uses numeric differentiation, and one
loses about half the working precision for each successive derivative.
Multiprecision is still being implemented, so, for now, the derivative
option
only gives moderately reasonable output for the first derivative (about 6-7
digits),
and less for the second derivative (about 3 digits). Beyond this, one
needs to use the USE_LONG_DOUBLE compile option in the MAkefile or higher
precision."


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Raymond Manzoni  
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 More options Nov 1, 7:03 pm
Newsgroups: sci.math
From: Raymond Manzoni <raym...@free.fr>
Date: Sun, 01 Nov 2009 15:03:55 +0100
Local: Sun, Nov 1 2009 7:03 pm
Subject: Re: about computing zeta'(s) in the critical strip
Raymond Manzoni a écrit :
> David Bernier a écrit :
>> I'm interested in methods for computing the derivative of the
>> Riemann zeta function, zeta', in the critical strip
>> 0<= Re(s) <= 1.

(snip)

>    Some references provided in these papers could be interesting too.

   For example :

   Levinson+Montgomery(1974) "Zeros of the derivatives of the Riemann
zeta-function" :
<http://www.kryakin.com/files/Acta_Mat_(2_55)/acta150_107/133/133_03.pdf>

   Conrey+Ghosh(1990?) "Zeros of derivatives of the Riemann
zeta-function near the critical line"
<http://books.google.fr/books?hl=fr&lr=&id=G02moOmuOX4C&oi=fnd&pg=PA95>

   Mezzadri(2002) "Random matrix theory and the zeros of zeta'(s)" (with
numerical investigations) : <http://arxiv.org/pdf/math-ph/0207044>

   Saidak(2004) "On the logarithmic derivative of the Euler product"
<http://tatra.mat.savba.sk/Full/29/14SAIDAK.ps>

 >
 > Or else, maybe someone has already computed some of the zeros
 > of zeta' in the critical strip, but I didn't find anything like
 > that.

   I tried a numerical search (using pari/gp) and found two zeros of
zeta' around these values (may be...) :
   0.96468562270568565 + 48.847159905068479085*I
   0.864623222098647   + 76.362807896467*I

   Hoping it helped,
                Raymond


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Axel Vogt  
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 More options Nov 1, 8:07 pm
Newsgroups: sci.math
From: Axel Vogt <&nore...@axelvogt.de>
Date: Sun, 01 Nov 2009 16:07:54 +0100
Local: Sun, Nov 1 2009 8:07 pm
Subject: Re: about computing zeta'(s) in the critical strip

Here 'are' some using Maple's command RootFinding[Analytic]:

.964685622705685650525780+48.8471599050684790854189*I
.848735328105403472052794+60.1408457820384239102073*I
.864622864426113300262053+76.3628078964670422358770*I
.780628004724644645328179+95.2929682713522169397106*I
.864103640598939499604406+88.1775174098810128722274*I
.856309339180055369726490+134.193836602386409228846*I
.943828539659771481951279+140.469959838197100688840*I
.662929906884329935358395+150.485953620246866996388*I
.966951342073371224843721+156.632667913413661808966*I
.863404697829980428874710+158.282522106715305651649*I
.635638410195870078269381+111.431017613746736506374*I
.847766864212029839013393+123.715269749934938660387*I


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Raymond Manzoni  
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 More options Nov 1, 9:12 pm
Newsgroups: sci.math
From: Raymond Manzoni <raym...@free.fr>
Date: Sun, 01 Nov 2009 17:12:45 +0100
Local: Sun, Nov 1 2009 9:12 pm
Subject: Re: about computing zeta'(s) in the critical strip
Axel Vogt a écrit :

    Nice! (my method was rather primitive...)

    To the OP note that the zeta function has more zeros in the same
imaginary range so that I'll add some zeros with real part larger than 1 :
2.46316186945432128587439505331+23.2983204927628579020109616266i
1.28649682226904769704411427839+31.7082500831159086049543521423i
1.38276360571167457578453372043+42.2909645545967298190807460934i
    (using this time the secant method on pari/gp)

    Fine continuation!
                Raymond


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David Bernier  
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 More options Nov 2, 10:01 am
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Mon, 02 Nov 2009 00:01:10 -0500
Local: Mon, Nov 2 2009 10:01 am
Subject: Re: about computing zeta'(s) in the critical strip
Marko Amnell wrote:
> "Raymond Manzoni" <raym...@free.fr> wrote:
>> David Bernier a écrit :
>>> I'm interested in methods for computing the derivative of the
>>> Riemann zeta function, zeta', in the critical strip
>>> 0<= Re(s) <= 1.

>>> One of the equivalents of the Riemann Hypothesis is
>>> that zeta' has no zero s with 0 <  Re(s) < 1/2 .

>>> Speiser [1934]:

[...]

Thanks to Raymond Manzoni and Marko Amnell for the useful information.

I've been experimenting with Michael Rubinstein's
lcalc command-line program.

For locating probable zeros of zeta', I've found
that knowing zeta'' is useful, once one
is near a probable zero of zeta'.

For the point s = 0.848735 + 60.140846*I,
I get:

bash$ ./lcalc  -d 2   -v -x 0.848735 -y 60.140846
1.082 0.1029

which means zeta''(s) ~= 1.082 + 0.1029*I .
By using the approximation zeta''(s) ~~= 1
and Newton's method, it's quite easy to get closer and
closer to a probable zero of zeta' near s.

Below I give the smallest value of | zeta'(.)| I found
near s = 0.848735 + 60.140846*I:

bash$ ./lcalc  -d 1   -v -x .84873530 -y 60.140845702
3.830269e-08 4.274359e-08 .

In other words,
zeta'(.8487353 + 60.140845702*I) ~= 0.00000004 + 0.00000004*I .

I haven't done so, but I think one could use the
Argument principle and numerically integrate zeta''/zeta'
in a small (but not too small) square or rectangle
around the probable zero to show that the square or rectangle
really does contain a zero of zeta' .  I might try that with
a square of side about 0.001.

A link to a web page about the Argument Principle:
http://mathworld.wolfram.com/ArgumentPrinciple.html

David Bernier


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David Bernier  
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 More options Nov 2, 11:29 am
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Mon, 02 Nov 2009 01:29:19 -0500
Local: Mon, Nov 2 2009 11:29 am
Subject: Re: about computing zeta'(s) in the critical strip
David Bernier wrote:

[...]

> Below I give the smallest value of | zeta'(.)| I found
> near s = 0.848735 + 60.140846*I:

> bash$ ./lcalc  -d 1   -v -x .84873530 -y 60.140845702
> 3.830269e-08 4.274359e-08 .

> In other words,
> zeta'(.8487353 + 60.140845702*I) ~= 0.00000004 + 0.00000004*I .

[...]

Using PARI-gp I get further:

? (zeta(%62) - zeta(%62+delta))/delta
%65 = 1.2715731464878770130 E-11 + 4.321841984664728360 E-11*I
[derivative is very close to zero.]

? delta
%66 = 1.0000000000000000000000000000000000000 E-20
? %62
%67 = 0.84873532809000000000000000000000000000 +
60.140845782000000000000000000000000000*I

"%62" is the value on output-line number 62.

So zeta'(0.84873532809 + 60.140845782) ~= 0.

David Bernier

P.S.  60.140845782 is close to a local maximum of the
       Riemann-Siegel Z(.) function, or
       RiemannSiegelZ in Mathematica.

Cf.:
http://reference.wolfram.com/legacy/v5/Built-inFunctions/Mathematical...


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David Bernier  
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 More options Nov 2, 6:46 pm
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Mon, 02 Nov 2009 08:46:19 -0500
Local: Mon, Nov 2 2009 6:46 pm
Subject: Re: about computing zeta'(s) in the critical strip

Thanks additionally to Axel Vogt for the Maple computations.

The Riemann-Siegel Z function has a local minimum of -0.37 near t = 357.58.
I used Glen Pugh's Z-plotter to get this:
http://web.viu.ca/pughg/RiemannZeta/RiemannZetaLong.html

A local minimum of Z(t) where the absolute value of the minimum attained
is about 0.37 is quite small, for t ~ 357 .

Using lcalc and PARI-gp, I searched for a zero of zeta'
near s = 0.5 + 357.58*I .

After some time, I got:

? (zeta(%158 + 0.5 E-100) - zeta(%158 - 0.5 E-100))/(1.0 E-100)
%160 = -2.0529131546 E-34 -1.2558044177 E-34*I
? %158
%161 = 0.67492445948651172431513544516762825  +
357.57576692022870053439669037496992465*I

So for s = 0.6749244594865117 + 357.5757669202287005*I,
zeta'(s) ~= 0 .

PARI-gp has the advantage of being able to do
complex arithmetic, and also stores the output
of each command-line computation as %n, where
n --> the numeral for line number n, e.g.
%2 for output from  line 2.

I searched for more points where Z(t) has a local
extremum whose value (in absolute value) is
quite small.  If there are zeros of zeta' close by,
I wasn't able to find them with the limited methods and tools
I have, i.e. using lcalc at one point and PARI-gp.

A local minimum of Z(t) near
t = 376.079 attains about Z(t) = -0.19 .

Another local minimum of Z(t) is
for Z(946.222) ~= -0.081 .

 From reading the hypothesis in Theorem 3 of Yitang Zhang's
2001 Duke Math. J. paper, with a link given by
Raymond Manzoni being:
<http://eduunix.ccut.edu.cn/index2/math/202.38.126.65/mathdoc/Duke.Mat...>

it could be that zeros of zeta' with real part close to 0.5
tend to occur near a pair of very close zeros of zeta;
this would correspond to very close zeros of the Z(t)
function.  Also, in order to find zeros of zeta'
with with real part as close as possible to 0.5,
it seems reasonable to search for very close zeros
of Z(t), as I believe I read that
Z(t_0) = 0 and Z'(t_0) = 0 implies that zeta has
a double (or higher...) zero at 1/2 + i*t_0 .

David Bernier


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David Bernier  
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 More options Nov 2, 8:23 pm
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Mon, 02 Nov 2009 10:23:25 -0500
Local: Mon, Nov 2 2009 8:23 pm
Subject: Re: about computing zeta'(s) in the critical strip

This shows how one can accomplish the Newton iterative
method in PARI-gp: (for zeros of zeta')

%260 =
0.6159808652502243493441636295353630657935035232448022488850729948269200791 600256469641388865822549070137942004625719591011444230932177007267705602939 894378662566389476923435368427843967727976391216951517185305197348740676202 437164879272912758855253667222428085147212409839813104516038844796851234321 862426867417817534892046203133140476723510770506360409986523342535643727111 436606614765236499423448487471861937818613282790249
+
185.21481233805041460264258685118074193672124564800139489701487402164393008 191875817416938543897554343849563064270430557988775405303538802561712267104 327040951749637320372433714589213728907392972317834793054795336657783382912 368807687377490984571725867949497813163067854404905604245723258669536721457 773505706221133877067468548373459004026633856741139265425535889666112251258 36137545595347755103003717274167383786845386256705*I

? %260 -((zeta(%260+delta/2) - zeta(%260 - delta/2))/delta)/(((zeta(%260
+delta)-zeta(%260 ))/delta - (zeta(%260)-zeta(%260 - delta))/delta)/delta)

%261 =
0.6159808652502243493441636295353630657935035232448022488850729948269200791 600256469641388865822549070137942004625719591011444230932176782676290627407 5509372456689106277299810
+
185.21481233805041460264258685118074193672124564800139489701487402164393008 191875817416938543897554343849563064270430557988775405303538802104354510714 31276191243312226292493623396089602295715887*I

(zeta(%261+0.0000000000000000000001)-zeta(%261-0.0000000000000000000001))/0 .0000000000000000000002
%263 =
-2.040933048712946245420654183911984468085855615224331278046194451928279798 9677857007170548820578865077668292759767906
E-44 +
1.1397362696963610746730853441636642275298134490298296710634666816089367900 687222909370492667688224267939387852905115
E-44*I

? delta
%264 =
1.0000000000000000000000000000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000
E-200

The basic iterative step in Newton's method to
locate a zero of zeta' is:

? %260 -((zeta(%260+delta/2) - zeta(%260 - delta/2))/
   delta)/(((zeta(%260 +delta)-zeta(%260 ))/delta -
   (zeta(%260)-zeta(%260 - delta))/delta)/delta) [ENTER]

-->
%261 [a number]

Above, %260 should be close enough to a zero of zeta' so that
the iterations converge.

Then, replace %260 by %261 in the long line after the question mark
above.

I eventually get "division by zero".  PARI-gp "plays" with the
significant figures or something.  Appending many 0s
to the real part, then the Imaginary part and combining
as: a + b*I  seems to restore more significant digits.

David Bernier


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Raymond Manzoni  
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 More options Nov 3, 5:37 am
Newsgroups: sci.math
From: Raymond Manzoni <raym...@free.fr>
Date: Tue, 03 Nov 2009 01:37:28 +0100
Local: Tues, Nov 3 2009 5:37 am
Subject: Re: about computing zeta'(s) in the critical strip
David Bernier a écrit :
(snip)

>> Thanks additionally to Axel Vogt for the Maple computations.

>> The Riemann-Siegel Z function has a local minimum of -0.37 near t =
>> 357.58.
>> I used Glen Pugh's Z-plotter to get this:
>> http://web.viu.ca/pughg/RiemannZeta/RiemannZetaLong.html

    Another (possibly more confusing) applet is available on Matthew
Watkins' site about zeta :
<http://www.secamlocal.ex.ac.uk/people/staff/mrwatkin//zeta/CSExplorer...>
    (select Riemann Siegel at the bottom left, choose the Y offset
and... try to avoid using the scrollbar at the bottom or you'll get out
of the critical line, lose the fast Riemann-Siegel evaluation and have
to be patient... ;-))

    Some of these points (search 'Lehmer's Phenomenon') are provided in
Edwards' excellent book about zeta :
<http://books.google.com/books?id=5uLAoued_dIC&pg=PA179>

    Example : for t ~= 17143.8039 the maximum is around 0.002153
    using the secant method (*) I found that
zeta'(0.5006167337067389436048937 + 17143.804216272698515881722i) was
nearly 0

   If there are zeros of zeta' close by,

    Yes pari/gp will remove the non-significative digits so that, for
example, if you evaluate zetap(z)= (zeta(z+eps/2)-zeta(z-eps/2))/eps
    at a point z such that zeta'(z)=0 you'll lose nearly -log_10(eps)
digits (every time!).

    A useful trick is to 'force' the default precision by replacing
    zetap(z) with zetap(precision(z,default(realprecision)))

    (by the way in a script default(realprecision, n) allows too to
change the default precision to n)

    You'll still get "division by zero" at the end but probably because
you were subtracting two equal values at the denominator!

    Pleasant Explorations!
                Raymond

(*) Script I used in pari/gp <http://pari.math.u-bordeaux.fr/download.html>

eps=1e-40;
\p 200
zetap(x)=(zeta(x+eps/2)-zeta(x-eps/2))/eps;
zetas(x)=(zeta(x+eps/2)-2*zeta(x)+zeta(x-eps/2))/eps^2;

fn(x)=x-zetap(x)/zetas(x)
fs(x)=r=x-zetap(x)*(x-xp)/(zetap(x)-zetap(xp));xp=x;r

xp=0.5+17143.8*I
fn(%)
fs(precision(%,200))
(iterating the last line until 'division by zero' ;-))

(iterating fn alone (Newton-Raphson) didn't converge most of the time...)


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David Bernier  
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 More options Nov 3, 6:58 am
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Mon, 02 Nov 2009 20:58:58 -0500
Local: Tues, Nov 3 2009 6:58 am
Subject: Re: about computing zeta'(s) in the critical strip

For the probable zero of zeta' you found, I get the approximation:

s~= 0.500616733706738943604893700414+17143.8042162726985158817223566*I

Then, 1/(Re(s) - 1/2) ~= 1621.445  .

I wonder if there are conjectures or guesses as to the true
asymptotics of
(Re(s) - 1/2) in terms of Im(s), for zeros s = beta' + gamma'
of zeta', where gamma' > 0 and letting gamma' become
arbitrarily large ...

Thanks for the info. on the behaviour of PARI-gp with
respect to significant digits in computations , left
unsnipped below.

David Bernier

[...]


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David Bernier  
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 More options Nov 3, 1:45 pm
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Tue, 03 Nov 2009 03:45:22 -0500
Local: Tues, Nov 3 2009 1:45 pm
Subject: Re: about computing zeta'(s) in the critical strip

Richard Brent mentioned a "Lehmer pair" in his 1979 article about
verifying RH for the first 75,000,000 non-trivial zeros.

As I understand it, with n = 41,820,581  the pair of zeros is the n'th
and the (n+1)st, where he found that
max_{t from Im(rho_n) to Im(rho_{n+1})} |Z(t)| < 0.00000248 .

[ rho_n is the n'th non-trivial zero].

I believe this is for t ~=  18882503.9 ,
and using a C program with Euler-MacLaurin summation,
I find that Z attains between Im(rho_n) and Im(rho_{n+1})
about as follows:

Z(18882503.90157) ~= 0.000002476

which is in line with Brent's results.


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David Bernier  
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 More options Nov 4, 12:26 pm
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Wed, 04 Nov 2009 02:26:31 -0500
Local: Wed, Nov 4 2009 12:26 pm
Subject: Re: about computing zeta'(s) in the critical strip
David Bernier wrote:

[...]

[...]

I have 'lcalc' pre-compiled, as distributed by M. Rubinstein.  This uses
64-bit doubles, I believe.  As for PARI-gp, evaluating
zeta(sigma +i*t) for t ~= 18882503.9 takes a lot of time
(maybe an hour or so).  One result returned by PARI-gp
is this:
? zeta(0.5000227046 +  18882503.90177114*I)
%1 = 0.00000102513240401800620447999232271568910311260563490669721490611
  - 0.000000247134107511231289945163352238926148478404827421149565046384*I

Euler-Maclaurin summation for zeta is described in Section 6.4
of Edwards' book, and programming it for
evaluating zeta(sigma +i*t) is just a bit more work than
programming it for evaluating zeta(1/2 +i*t).

Some compiled languages have a 'long double' floating point
type, with more significant bits than a 'double' type.

Perhaps | zeta'| is small at the point 1/2 +i*t where t
satisfies Z'(t) = 0, and t is in between two zeros of Z(.)
corresponding to a Lehmer pair:

Cf.:
http://en.wikipedia.org/wiki/Z_function

zeta(1/2 + i*t) = exp(-i theta(t)) Z(t),
then zeta'(1/2 + i*t) =  ....
[ the problem lies in trying to take or taking complex derivatives
   of the continuations of  exp(-i theta(t)) and Z(t),
   if they exist in some neighborhood.]

David Bernier


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David Bernier  
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 More options Nov 4, 3:31 pm
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Wed, 04 Nov 2009 05:31:35 -0500
Local: Wed, Nov 4 2009 3:31 pm
Subject: Re: about computing zeta'(s) in the critical strip
David Bernier wrote:

[...]

> I have 'lcalc' pre-compiled, as distributed by M. Rubinstein.  This uses

I was wrong about compilation.  After unzipping and re-creating the
archived files and directories, the source code is compiled after
one gives the 'make' command.

David Bernier


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David Bernier  
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 More options Nov 5, 3:22 pm
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Thu, 05 Nov 2009 05:22:58 -0500
Local: Thurs, Nov 5 2009 3:22 pm
Subject: Re: about computing zeta'(s) in the critical strip

[...]

In the Newton-Raphson method, the value (A) (or %2) below
was my starting point as an approximation to
a zero of  zeta' .  Using finite difference quotients,
I got the approximation to the second derivative of
zeta, at A, which appears in (C) below.

I also had an approximation to zeta' at A [not shown].
So applying finite differences Newton's method to
the approximate probable zero in (A) [ for the
function zeta' ] , one step led to (B) below,
which differs from (A) in absolute value by
about 6 E-12 .  The approximation (B) to
a probable zero of zeta' should be better
than approximation (A), if all went well.

I used PARI-gp, and each zeta evaluation seemed to
take an hour or two, if not more.

? %2
0.500000252347038803   + 18882503.901568975845293608*I     (A)

? %20
0.50000025235197704296 + 18882503.90156897584828762548*I   (B)

zeta''(%2) ~= 62.035774 - 38.815900*I     (C)

David Bernier


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Raymond Manzoni  
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 More options Nov 9, 2:15 am
Newsgroups: sci.math
From: Raymond Manzoni <raym...@free.fr>
Date: Sun, 08 Nov 2009 22:15:20 +0100
Local: Mon, Nov 9 2009 2:15 am
Subject: Re: about computing zeta'(s) in the critical strip
David Bernier a écrit :
(snip)

   Perhaps that some recent papers of Nathan Ng could interest you :
   <http://arxiv.org/find/math/1/au:+Ng_N/0/1/0/all/0/1>
   especially his discussion in "Extreme values of zeta prime rho"

   See too Garaev's "On small distances between ordinates of zeros of
zeta(s) and zeta'(s)"
<http://www.math.boun.edu.tr/instructors/yildirim/paper/OnSmallDistanc...>

   Concerning fast evaluation of Riemann zeta you may look at Hiary's
   "Fast methods to compute the Riemann zeta function" and references
provided there : <http://fr.arxiv.org/abs/0711.5005v1>

   Euler MacLaurin is easy to implement but requires evaluation of about
t terms (t= Im(s)) of the partial zeta sum. I think it is often used to
find the small zeros with high precision (and probably in pari/gp...).
   Riemann-Siegel is not very accurate for small values of t but pretty
good for large values since needing only around sqrt(t/(2 pi)) terms of
the zeta sum.
   Both methods are described in the Edwards book even if Riemann-Siegel
is harder to implement (the error term is the hard part!) and restricted
there to the case Re(s)= 1/2. The two applets referenced use R-S on the
critical line (I think it could be implemented for Re(s)<>1).

   For an implementation see Ken Takusagawa's "Tabulating values of the
Riemann-Siegel Z function along the critical line" :
   <http://web.mit.edu/kenta/www/six/parallel/2-Final-Report.html>
   see too Tuck's "Riemann-Siegel sums via stationary phase"
  <https://www.austms.org.au/Publ/Bulletin/V72P2/pdf/722-5212-Tuck-v.pdf>

   Regards,
        Raymond


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David Bernier  
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 More options Nov 9, 3:47 pm
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Mon, 09 Nov 2009 05:47:03 -0500
Local: Mon, Nov 9 2009 3:47 pm
Subject: Re: about computing zeta'(s) in the critical strip

For now, I'm interested mostly in numerical approximation of zeros
beta' + i*gamma' of the derivative of Riemann zeta, with
beta' very close to 1/2.  Empirically, good places to start
seem to include the vicinity of Lehmer pairs.

For the Lehmer pair with imaginary part ~= 17143.8, PARI-gp
took perhaps 2 or 3 hours per 38-digit zeta computation at
a height t ~= 17143.8.

Moving on to the Lehmer pair with imaginary parts
about 388,588,886 mentioned in Odlyzko et al, the
zeta computations become more time-consuming if
one wants 12+ digits accuracy.

"A New Lehmer pair of zeros and a new lower bound for the de
Bruijn-Newman constant LAMBDA" [1993]
authors: G. Csordas, A. M. Odlyzko, W. Smith, and R. S. Varga.

That was based on "by-products" of RH verification for hundreds
of millions of non-trivial zeros in the 1980's by the Dutch,
e.g.
LRW86:
http://en.wikipedia.org/wiki/Riemann_hypothesis#Numerical_calculations
[ Australian R. Brent is linked to J. van de Lune, H. J. J. te Riele, D.
T. Winter via RH verification before 1986].

Cf.:
< http://www.dtc.umn.edu/~odlyzko/doc/cnt.html > , 10th paper or so ...

The Lehmer pair appears there as
t = 3.888 588 860 022 851 203 e+08,
t = 3.888 588 860 023 936 899 e+08

equivalent to
t = 388,858,886.0022851203 and
t = 388,858,886.0023936899 .

PARI-gp's built-in zeta(.) can probably do the zeta evaluations, but
the time it took for a Lehmer pair with t ~= 18,000,000 (about 3 hours)
doesn't bode well for t ~= 388,858,886.002.

It seems to me that for numerical computation of zeros of zeta',
a lot of accuracy in the zeta function values is desirable, since
zeta varies slowly near a zero of zeta' such as the one
with imaginary part about 18,000,000 .  I think this argues for
Euler-Maclaurin summation.  Even "long doubles" seem to give
only about 11 or 12 decimal digits (after the decimal point)
for the two zeta zeros at height ~= 388,858,886.02 .

One workable option is to sum 1 billion or so terms in
PARI-gp of both   cos(t log(n))/sqrt(n) [n = 1 ... 10^9]
and  sin(t log(n))/sqrt(n) [n = 1 ... 10^9]
and add a few terms in the Euler-Maclaurin expansion,
in the PARI-gp environment.

I've done the 1 billion cosine partial sum, and it took a few hours.

Another possibility for 20 decimal+ zeta evaluations is through
the use of Victor Shoup's NTL library:

Cf.:
< http://www.shoup.net/ntl/ >

So far, I've been able to gunzip the *.gz file, extract the *.tar
archive, run ./configure   [ default] , 'make', and 'make check'
[ Tests Ok ].  Then, 'make install' as root:  # make install .

Next, I'd want to write a program that uses NTL to do simple
transcendental function computations using "quad_floats",
which offer 106-bit precision.

>   Both methods are described in the Edwards book even if Riemann-Siegel
> is harder to implement (the error term is the hard part!) and restricted
> there to the case Re(s)= 1/2. The two applets referenced use R-S on the
> critical line (I think it could be implemented for Re(s)<>1).

Since for the time being I just want to compute zeta' zeros
which are or could be near a  few selected Lehmer pairs of zeros,
I find Euler-Maclaurin summation more appealing than the
Riemann-Siegel formula.

----

In the article
http://sci.tech-archive.net/Archive/sci.math/2009-10/msg02124.html  ,
I was wondering if Z(t) having no negative local maximum when t>100
& Z(t) having no positive local minimum when t>100
was enough to imply the Riemann Hypothesis.

In the problem statement of RH at ClayMath, Bombieri mentions
an RH equivalent:

"The Riemann hypothesis is equivalent to the statement that
all local maxima of xi(t) are positive and
all local minima are negative, [...] "

Cf.:
< http://www.claymath.org/millennium/Riemann_Hypothesis/ >

--->  Official Problem Description, page 6 of 11.

Starting from:
"all local maxima of xi(t) are positive and
all local minima are negative"

I've been thinking about relations with:
"Z(t) has no negative local maximum when t>100
& Z(t) has no positive local minimum when t>100"

I know well that the average of |Z(t)| grows slowly
as t>0 increases.  I don't know xi(t) so well,
however if the average value of |xi(t)| near t
changes fast as the point on the critical line
corresponding to t moves up the line Im(s) = 1/2,
perhaps one can't rule out
"all local maxima of xi(t) are positive and
all local minima are negative" Failing,
while "Z(t) has no negative local maximum when t>100
& Z(t) has no positive local minimum when t>100" might still
Hold ...

I'd be rather interested in knowing if:
Z(t) has no negative local maximum when t>100
& Z(t) has no positive local minimum when t>100" implies RH ...

Regards,

David Bernier


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David Bernier  
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 More options Nov 14, 7:17 am
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Fri, 13 Nov 2009 21:17:34 -0500
Local: Sat, Nov 14 2009 7:17 am
Subject: Re: about computing zeta'(s) in the critical strip

[...]

I don't know much about C++, and I didn't find sample code
with commented examples that really helped me.

David Bailey  and others have developed MPFUN90 and other
Fortran or C++ libraries for high-precision arithmetic,
and I'll probably experiment with one of the libraries
some time.

Link to David Bailey web page:
< http://crd.lbl.gov/~dhbailey/mpdist/ >

David Bernier


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Dave Seaman  
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 More options Nov 14, 7:19 pm
Newsgroups: sci.math
From: Dave Seaman <dsea...@no.such.host>
Date: Sat, 14 Nov 2009 14:19:37 +0000 (UTC)
Local: Sat, Nov 14 2009 7:19 pm
Subject: Re: about computing zeta'(s) in the critical strip

On Fri, 13 Nov 2009 21:17:34 -0500, David Bernier wrote:
> I don't know much about C++, and I didn't find sample code
> with commented examples that really helped me.
> David Bailey  and others have developed MPFUN90 and other
> Fortran or C++ libraries for high-precision arithmetic,
> and I'll probably experiment with one of the libraries
> some time.
> Link to David Bailey web page:
>< http://crd.lbl.gov/~dhbailey/mpdist/ >
> David Bernier

GMP is an extended-precision library that can be used with C or C++.
It claims to be faster than any other bignum library.
<http://gmplib.org/>

--
Dave Seaman
Third Circuit ignores precedent in Mumia Abu-Jamal ruling.
<http://www.indybay.org/newsitems/2008/03/29/18489281.php>


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David Bernier  
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 More options Nov 15, 10:45 am
Newsgroups: sci.math
From: David Bernier <david...@videotron.ca>
Date: Sun, 15 Nov 2009 00:45:41 -0500
Local: Sun, Nov 15 2009 10:45 am
Subject: Re: about computing zeta'(s) in the critical strip

Thanks.  I downloaded  mpfun90.tar.gz from David Bailey's web site.
Unzipping and extracting the archive went without a problem.
As building, I changed the name of the Fortran compiler to
"gfortran", I think, and removed any calls to timing functions.
Since I also tried the ARPREC package, it could be something
like removing calls to "etime" for mpfun90, and calls to
"second()" for the ARPREC package.

The problem I had with ARPREC was getting the "includes" right for my
own programs.

For mpfun90, I was able to run test programs that get built when
one does "make" [ this uses what's in the furnished Makefile ].

One of these is the executable quadts, which does
15 numerical integration problems.  I'm quite impressed:
about 400D precision except Problem 15 (something not
quite right there) in a few minutes.

I uploaded the output here:
< http://berniermath.net/mp90quadrature.txt >

The CPU times mean nothing, as I disabled timing.

So I'm thinking about getting the right compiler options
for mpfun90, for my own source code.  AFAIK, the executable
_quadts_ was built using directives, such as those in the
Makefile.

Perhaps there's a "verbose" option with  GNU make, so that
I could see what the compiler options were when building
_quadts_  or other included test programs ...

David Bernier


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