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miki  
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 More options Nov 7, 2:18 pm
Newsgroups: sci.math
From: miki <miki.li...@gmail.com>
Date: Sat, 7 Nov 2009 01:18:24 -0800 (PST)
Local: Sat, Nov 7 2009 2:18 pm
Subject: Question on bounded variation functions
Hello All,

The well-known definition of bounded variation functions is about
their behavior on closed intervals.
To say, "The total variation of real-valued function f, defined on an
interval [a, b] belongs to R is the quantity V_a_b_(f) = sup(sum(|f(x_i
+1) - f(x_i)|)) of all partitions of the interval considered", (etc.)

My question is, can I use or define total variation for a half-open
interval, say, [a, b)?

In any case, my intention is to define (or use) the following: for any
eps > 0 the total variation of the function
f on the interval [a, b - eps] is finite. Is it the same as to say
that the total variation of a function over the half-open interval [a,
b) is finite?

Regards,
Miki


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Tonico  
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 More options Nov 7, 5:53 pm
Newsgroups: sci.math
From: Tonico <Tonic...@yahoo.com>
Date: Sat, 7 Nov 2009 04:53:26 -0800 (PST)
Local: Sat, Nov 7 2009 5:53 pm
Subject: Re: Question on bounded variation functions
On Nov 7, 11:18 am, miki <miki.li...@gmail.com> wrote:

Try with f(x) = 1/x  and (0,1]: for any e > 0 the total variation of f
(x) in [e,1] is finite  but not so in (0,1]

Tonio


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David C. Ullrich  
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 More options Nov 7, 7:18 pm
Newsgroups: sci.math
From: David C. Ullrich <dullr...@sprynet.com>
Date: Sat, 07 Nov 2009 08:18:22 -0600
Local: Sat, Nov 7 2009 7:18 pm
Subject: Re: Question on bounded variation functions
On Sat, 7 Nov 2009 01:18:24 -0800 (PST), miki <miki.li...@gmail.com>
wrote:

>Hello All,

>The well-known definition of bounded variation functions is about
>their behavior on closed intervals.
>To say, "The total variation of real-valued function f, defined on an
>interval [a, b] belongs to R is the quantity V_a_b_(f) = sup(sum(|f(x_i
>+1) - f(x_i)|)) of all partitions of the interval considered", (etc.)

>My question is, can I use or define total variation for a half-open
>interval, say, [a, b)?

Yes.

>In any case, my intention is to define (or use) the following: for any
>eps > 0 the total variation of the function
>f on the interval [a, b - eps] is finite. Is it the same as to say
>that the total variation of a function over the half-open interval [a,
>b) is finite?

Of course not - the total variation on [a, b-eps] could be finite
for every eps > 0 but tend to infinity as eps -> 0.

If the total variation on [a,b-eps] is _bounded_ for eps > 0
then the total variation on [a,b) is finite.

>Regards,
>Miki

David C. Ullrich

"Understanding Godel isn't about following his formal proof.
That would make a mockery of everything Godel was up to."
(John Jones, "My talk about Godel to the post-grads."
in sci.logic.)


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miki  
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 More options Nov 8, 12:01 am
Newsgroups: sci.math
From: miki <miki.li...@gmail.com>
Date: Sat, 7 Nov 2009 11:01:25 -0800 (PST)
Local: Sun, Nov 8 2009 12:01 am
Subject: Re: Question on bounded variation functions
On Nov 7, 4:18 pm, David C. Ullrich <dullr...@sprynet.com> wrote:

Thanks,

My question is, can I use or define total variation for a half-open

> >interval, say, [a, b)?

> Yes.

So, what is the definition of total variation on the interval [a, b)?
How can I write the sum if the left-end of the interval is open?

If I take the function f(x)=1/(x-5) for example,
it is of bounded variation on [4, 5 - e] for every e > 0 as long as e
does not tends to zero (so actually, its not for every e...)
OK, so what about saying that it is of bounded variation on [4, 5).
Now is it correct? If so, whats the meaning of it in terms of
total variation? how can I compute its total variation?

thanks
Miki


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David C. Ullrich  
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 More options Nov 8, 2:42 am
Newsgroups: sci.math
From: David C. Ullrich <ullr...@math.okstate.edu>
Date: Sat, 07 Nov 2009 15:42:22 -0600
Local: Sun, Nov 8 2009 2:42 am
Subject: Re: Question on bounded variation functions
On Sat, 7 Nov 2009 11:01:25 -0800 (PST), miki <miki.li...@gmail.com>
wrote:

If I is any interval (including [a,b], (a,b), R, etc) and f is defined
on I then the total variation of f on I is the sup of

  V(f,I) = sum |f(t_j) - f(t_{j-1}|

over all choices of numbers t_0, .., t_n in I with t_{j-1} < t_j.

And then we say that f has bounded variation on I if V(f,I) is finite.

>If I take the function f(x)=1/(x-5) for example,
>it is of bounded variation on [4, 5 - e] for every e > 0 as long as e
>does not tends to zero (so actually, its not for every e...)

Yes, for every e. You're confused about the difference between
"finite" and "bounded".

For _every_ e > 0 (well, we also want e < 1) we have

  V(f, [4, 5-e]) < infinity.

But V(f, [4, 5-e]) is not bounded, and in particular

   V(f, [4,5)) = infinity.

>OK, so what about saying that it is of bounded variation on [4, 5).
>Now is it correct?

No.

> If so, whats the meaning of it in terms of
>total variation? how can I compute its total variation?

From the definition above. The computation is very simple here
because f is monotone.


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miki  
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 More options Nov 8, 11:20 am
Newsgroups: sci.math
From: miki <miki.li...@gmail.com>
Date: Sat, 7 Nov 2009 22:20:38 -0800 (PST)
Local: Sun, Nov 8 2009 11:20 am
Subject: Re: Question on bounded variation functions
On Nov 7, 11:42 pm, David C. Ullrich <ullr...@math.okstate.edu> wrote:

Thanks.
I did confuse between "finite" and "bounded". Well, I care only for
finite.
Nevertheless, I think I have a confusion also about the open and
closed intervals.
Meaning,

"for every e > 0 ... "

You wrote:

1. V(f, [4, 5-e]) < infinity.
I ask why. Namely, If I say for "every e > 0" it means that I can take
e to be as small as I want, so I can take also the limit toward zero.
isn't it? Of course, in the limit we have problems so how can the
total variation be not infinite.

2. V(f, [4, 5)) = infinity.
This case is understood.

2. V(f, [4, 5-e)) = infinity.
What about this expression? Is this as no. 2? What is the difference
from no. 1?

what about this case: f(x) = x
Is th total variation of f(x) over [0, 1) is finite now? why?

Thanks again,
Miki


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David C. Ullrich  
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 More options Nov 8, 6:54 pm
Newsgroups: sci.math
From: David C. Ullrich <dullr...@sprynet.com>
Date: Sun, 08 Nov 2009 07:54:01 -0600
Local: Sun, Nov 8 2009 6:54 pm
Subject: Re: Question on bounded variation functions
On Sat, 7 Nov 2009 22:20:38 -0800 (PST), miki <miki.li...@gmail.com>
wrote:

No, looking below it seems the confusion is more basic than that.

>Meaning,

>"for every e > 0 ... "

>You wrote:

>1. V(f, [4, 5-e]) < infinity.
>I ask why. Namely, If I say for "every e > 0" it means that I can take
>e to be as small as I want, so I can take also the limit toward zero.
>isn't it?

No, it doesn't mean that!

If the V(f, [4, 5-e])  were _bounded_ for e > 0 then you
could say that. But just supposing that V(f, [4, 5-e])  is
finite for every e > 0 says nothing about boundedness
and also nothing about the limit.

Look. Is the following true or false?

(i) e > 0 for every e > 0.

I hope you agree that's true - if (i) is false then
you have to give me an example of an e > 0 such
that e is not > 0.

Now according to you, since (i) is true for every e > 0
it follows that we can take the limit. We take the limit
as e -> 0 and we get the following statement:

(ii) 0 > 0.

Which is false.

That example has nothing to do with bounded variation.
The point to the example is to convince you that what
you're confused about _also_ has nothing to do with
bounded variation - the things you think about how "of
course if this is true then we can take the limit" are
simply not so.

David C. Ullrich

"Understanding Godel isn't about following his formal proof.
That would make a mockery of everything Godel was up to."
(John Jones, "My talk about Godel to the post-grads."
in sci.logic.)


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miki  
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 More options Nov 9, 12:30 pm
Newsgroups: sci.math
From: miki <miki.li...@gmail.com>
Date: Sun, 8 Nov 2009 23:30:08 -0800 (PST)
Local: Mon, Nov 9 2009 12:30 pm
Subject: Re: Question on bounded variation functions
On Nov 8, 3:54 pm, David C. Ullrich <dullr...@sprynet.com> wrote:

I agree with all your arguments.
It is difficult to understand such kind of content via the internet,
so I tend to ask some questions like no 1. just to be sure.

So, what about the case of no. 2. where we talk about the interval [4,
5-e)
and about the no. 3 where the interval is [4, 5).
I remind you that the function is f(x) = 1/(x-5)

and I am interesting only with the total variation being finite for
every epsilon on the mentioned
intervals. I dont care for boundness at all.

I guess that the case for half open interval is different ... is it?
if so why?
I guess that there is a different between [4, 5-e) (for e > 0) and the
case of [4, 5).

You know what, I think I know the answer, please just confirm it.

To say, The case of [4, 5-e) is like case of [4, 5-e] (e > 0), namely,
the total variation is finite
for every e > 0.

The case of [4, 5) is problematic since by the definition of total
variation: it is the sup
of all partitions, so its kind of taking the limit on the interval [4,
5) on all the partitions, so I can build a strictly monotone
increasing set of sum over all the partitions and take limit which is
infinity, so ... the total variation is infinite. Is it correct?

Thanks a lot,
Miki


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David C. Ullrich  
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 More options Nov 9, 7:07 pm
Newsgroups: sci.math
From: David C. Ullrich <dullr...@sprynet.com>
Date: Mon, 09 Nov 2009 08:07:40 -0600
Local: Mon, Nov 9 2009 7:07 pm
Subject: Re: Question on bounded variation functions
On Sun, 8 Nov 2009 23:30:08 -0800 (PST), miki <miki.li...@gmail.com>
wrote:

What about this case? I've already answered all the
questions you had about this.

David C. Ullrich

"Understanding Godel isn't about following his formal proof.
That would make a mockery of everything Godel was up to."
(John Jones, "My talk about Godel to the post-grads."
in sci.logic.)


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