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Edgar E. Escultura  
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 More options Nov 5, 3:24 pm
Newsgroups: sci.math
From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Thu, 05 Nov 2009 05:24:10 EST
Local: Thurs, Nov 5 2009 3:24 pm
Subject: Two fatal defects of Wiles' proof of FLT
Two Fatal Defects of Andrew Wiles’ Proof of FLT
By E. E. Escultura

1) The field axioms of the real number system are inconsistent; Felix Brouwer and this blogger provided counterexamples to the trichotomy axiom and Banach-Tarski to the completeness axiom, a variant of the axiom of choice. Therefore, the real number system is ill-defined and FLT being formulated in it is also ill-defined. What it took to resolve this conjecture was to first free the real number system from contradiction by reconstructing it as the new real number system on three simple consistent axioms and reformulating FLT in it. With this rectification of the real number system, FLT is well-defined and resolved by counterexamples proving that it is false. (Main reference: Escultura, E. E., The new real new real number system and discrete computation and calculus, Neural, Parallel and Scientific Computations, 17 (2009), 59 – 84).

2) The other fatal defect is that the complex number system that Wiles used in the proof being based on the vacuous concept i is also inconsistent. The element i is the vacuous concept: the root of the equation x^2 + 1 = 0 which does not exist and is denoted by the symbol i = sqrt(-1) from which follows that,

i = sqrt(1/-1) = sqrt 1/sqrt(-1) = 1/i = i/i^2 = -i   or

1 = -1 (division of both sides by i),

2 = 0,  1 = 0, i = 0, and, for any real number x, x = 0,

and the entire real and complex number systems collapse. The remedy is in the appendix to the paper, The generalized integral as dual to Schwarz distribution, in press, Nonlinear Studies.

Another example of a vacuous concept is the greatest integer. Let N be the greatest integer. By the trichotomy axiom one and only one of the following axioms holds: N < 1, N = 1, N > 1. The first inequality is clearly false. If N > 1, then N^2 > N, contradicting the choice of N. therefore N = 1. This is the original statement of the Perron paradox and it is blamed on the vacuous concept N. In general, any vacuous concept yields a contradiction.

E. E. Escultura
Research Professor
V. Lakshmikantham Institute for Advanced Studies
GVP College of Engineering, JNT University
Madurawada, Vishakhapatnam, AP, India
http://users.tpg.com.au/pidro/


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Dirk Van de moortel  
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 More options Nov 5, 4:07 pm
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From: "Dirk Van de moortel" <dirkvandemoor...@nospAm.hotmail.com>
Date: Thu, 5 Nov 2009 12:07:15 +0100
Local: Thurs, Nov 5 2009 4:07 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
Edgar E. Escultura <escultu...@yahoo.com> wrote in message
  1117368396.14753.1257416680869.JavaMail.r...@gallium.mathforum.org

On Usenet he can write whatever he wants about his current
title, but it looks like the institute forced him to include the
Emeritus qualifier on his website :-)

Yes, people like this are allowed on the street.

Dirk Vdm


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MMM  
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 More options Nov 5, 7:44 pm
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From: "MMM" <w...@wako.net>
Date: Thu, 5 Nov 2009 06:44:53 -0800
Local: Thurs, Nov 5 2009 7:44 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
Double idiot squared, plus infinity, plus one, squared, tied in a sack, and
thrown over the back of a donkey.  Times two.

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CapCity  
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 More options Nov 6, 2:16 am
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From: "CapCity" <C...@City.com>
Date: Thu, 5 Nov 2009 16:16:25 -0500
Local: Fri, Nov 6 2009 2:16 am
Subject: Re: Two fatal defects of Wiles' proof of FLT

"MMM" <w...@wako.net> wrote in message news:hcuobh$m8f$1@aioe.org...
> Double idiot squared, plus infinity, plus one, squared, tied in a sack,
> and thrown over the back of a donkey.  Times two.

= EEE = 3E

Right?


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Ken Quirici  
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 More options Nov 6, 4:01 am
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From: Ken Quirici <kquir...@yahoo.com>
Date: Thu, 5 Nov 2009 15:01:34 -0800 (PST)
Local: Fri, Nov 6 2009 4:01 am
Subject: Re: Two fatal defects of Wiles' proof of FLT
On Nov 5, 5:24 am, "Edgar E. Escultura" <escultu...@yahoo.com> wrote:

> Two Fatal Defects of Andrew Wiles’ Proof of FLT
> By E. E. Escultura

> 1) The field axioms of the real number system are inconsistent; Felix Brouwer and this blogger provided counterexamples to the trichotomy axiom and Banach-Tarski to the completeness axiom, a variant of the axiom of choice. Therefore, the real number system is ill-defined and FLT being formulated in it is also ill-defined. What it took to resolve this conjecture was to first free the real number system from contradiction by reconstructing it as the new real number system on three simple consistent axioms and reformulating FLT in it. With this rectification of the real number system, FLT is well-defined and resolved by counterexamples proving that it is false. (Main reference: Escultura, E. E., The new real new real number system and discrete computation and calculus, Neural, Parallel and Scientific Computations, 17 (2009), 59 – 84).

> 2) The other fatal defect is that the complex number system that Wiles used in the proof being based on the vacuous concept i is also inconsistent. The element i is the vacuous concept: the root of the equation x^2 + 1 = 0 which does not exist and is denoted by the symbol i = sqrt(-1) from which follows that,

> i = sqrt(1/-1) = sqrt 1/sqrt(-1) = 1/i = i/i^2 = -i   or

Actually, could somebody explain why this is NOT
valid:

i = sqrt(1/-1) = sqrt 1/sqrt(-1) = 1/i,

therefore

i^2 = 1,

therefore -1 = 1?

I tried a few examples like

sqrt(9/4) = sqrt(9)/sqrt(4) = 3/2 = 1.5

OR

sqrt(9/4) = sqrt(2.25) = 1.5.

So what is my molasses mind missing?


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Tim Little  
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 More options Nov 6, 5:32 am
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From: Tim Little <t...@little-possums.net>
Date: 06 Nov 2009 00:32:35 GMT
Local: Fri, Nov 6 2009 5:32 am
Subject: Re: Two fatal defects of Wiles' proof of FLT
On 2009-11-05, Ken Quirici <kquir...@yahoo.com> wrote:

> Actually, could somebody explain why this is NOT
> valid:

> i = sqrt(1/-1) = sqrt 1/sqrt(-1) = 1/i,

The second equality is unjustified.  It requires a property of sqrt
that holds in the reals, but cannot be extended to the whole complex
field.

When defining sqrt as a function, you have to choose which roots to
take for the nonzero values.  With reals the most useful choice is the
set of all positive roots, as they are closed under multiplication.
However in the complex field there is no possible choice that is
closed under multiplication.  At best you can say that

  sqrt(x) sqrt(y) = +/- sqrt(x y).

So the original "paradox" becomes:

 i = sqrt(1/-1) = +/- sqrt(1) / sqrt(-i) = +/- 1/i,

which is quite true.

- Tim


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A  
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 More options Nov 6, 8:54 am
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From: A <anonymous.rubbert...@yahoo.com>
Date: Thu, 5 Nov 2009 19:54:21 -0800 (PST)
Local: Fri, Nov 6 2009 8:54 am
Subject: Re: Two fatal defects of Wiles' proof of FLT
On Nov 5, 7:32 pm, Tim Little <t...@little-possums.net> wrote:

More generally, when one defines i as the square root of -1, one
chooses ONE of the two square roots of -1 in the complex numbers to be
i; the other is necessarily -i. The "paradox" above, and some portion
of Escultura's misunderstandings, is the result of failing to
distinguish between the two square roots of -1 in the complex numbers.

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Edgar E. Escultura  
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 More options Nov 6, 1:06 pm
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Fri, 06 Nov 2009 03:06:34 EST
Local: Fri, Nov 6 2009 1:06 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
Just as those who cannot do mathematics philosophise about it or write about its history those who cannot rebut a comment talk about something else.
E. E. Escultura

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Edgar E. Escultura  
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 More options Nov 6, 1:11 pm
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Fri, 06 Nov 2009 03:11:01 EST
Local: Fri, Nov 6 2009 1:11 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
When one cannot rebut a comment he resorts to name calling that only reveal intellectual inadequacy and emptiness at the top. E. E. Escultura

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Edgar E. Escultura  
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 More options Nov 6, 1:19 pm
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Fri, 06 Nov 2009 03:19:13 EST
Local: Fri, Nov 6 2009 1:19 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
Actually, traditional mathematicians choose one of the two square roots of -1 called principal value to avoid the contradiction. But this does not negate the fact that one can derive a contradiction from i. The root of this problem is the vacuous nature of i being the root of x^2 + 1 which does not exist. E. E. Escultura

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Edgar E. Escultura  
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 More options Nov 6, 1:29 pm
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Fri, 06 Nov 2009 03:29:03 EST
Local: Fri, Nov 6 2009 1:29 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
This is the only serious comment of this thread so far and it's deeply appreciated. The source of the contradiction, however, is that the concept i = the root of the equation x^2 + 1 = 0 among the real numbers does not exist. i.e., i is ill-defined. E. E. Escultura.

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Ken Quirici  
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 More options Nov 6, 8:32 pm
Newsgroups: sci.math
From: Ken Quirici <kquir...@yahoo.com>
Date: Fri, 6 Nov 2009 07:32:24 -0800 (PST)
Local: Fri, Nov 6 2009 8:32 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
On Nov 5, 10:54 pm, A <anonymous.rubbert...@yahoo.com> wrote:

Well the above two replies make eminent good sense!

It's so easy when someone explains it to you.


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A  
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 More options Nov 6, 8:53 pm
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From: A <anonymous.rubbert...@yahoo.com>
Date: Fri, 6 Nov 2009 07:53:19 -0800 (PST)
Local: Fri, Nov 6 2009 8:53 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
On Nov 6, 3:19 am, "Edgar E. Escultura" <escultu...@yahoo.com> wrote:

> Actually, traditional mathematicians choose one of the two square roots of -1 called principal value to avoid the contradiction. But this does not negate the fact that one can derive a contradiction from i. The root of this problem is the vacuous nature of i being the root of x^2 + 1 which does not exist. E. E. Escultura

What contradiction do you claim that one can derive from the existence
(in the complex numbers) of a square root of -1? There was an attempt
you made already in this thread but it was only based on your failure
to distinguish between i and -i. You also claim that Brouwer, Banach,
and Tarski constructed counterexamples to the generally recognized
properties of the real numbers. What are these counterexamples?

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Brian  
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 More options Nov 6, 11:57 pm
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From: Brian <tenn...@gmail.com>
Date: Fri, 6 Nov 2009 10:57:27 -0800 (PST)
Local: Fri, Nov 6 2009 11:57 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
On Nov 6, 1:29 am, "Edgar E. Escultura" <escultu...@yahoo.com> wrote:

> This is the only serious comment of this thread so far and it's deeply appreciated. The source of the contradiction, however, is that the concept i = the root of the equation x^2 + 1 = 0 among the real numbers does not exist. i.e., i is ill-defined. E. E. Escultura.

Correct me if I'm wrong, you can define C to be R[x]/<x^2+1>, the
quotient ring of the set of polynomials with real coefficients modded
out by the ideal generated by x^2+1.  The isomorphism sends x to i.
There is nothing ill-defined about that.

You can also define C by the set of ordered pairs of real numbers with
specific definitions for addition and multiplication for ordered pairs
of real numbers.  Again, nothing ill-defined about that.

Moreover, you seem to be suggesting that since a polynomial equation
has no real roots implies that C is ill-defined. Maybe you can explain
why I'm wrong but that's like saying that since 3x+1=-1 has no roots
among the integers that Q is ill-defined, and like saying that since
x^2 = 2 has no rational roots that the set of irrationals are ill-
defined.  There is a progression of number sets that allow for more
polynomial equations to be "solved" (ie, roots found), starting with
N, then Z, Q, R, and finally C.  That C is algebraically closed
implies that polynomials will not yield further number sets.


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fernando revilla  
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 More options Nov 6, 11:55 pm
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From: fernando revilla <frej0...@ficus.pntic.mec.es>
Date: Fri, 06 Nov 2009 13:55:42 EST
Local: Fri, Nov 6 2009 11:55 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT

E. E. Escultura wrote:
> 2) The other fatal defect is that the complex number
> system that Wiles used in the proof being based on
> the vacuous concept i is also inconsistent. The
> element i is the vacuous concept: the root of the
> equation x^2 + 1 = 0 which does not exist

But it's well known that R^2 together with adequate operations
sum and product, provide to R^2 a field structure which contains
a sub field isomorphic to the standard (R, +, *). So there are objects,
for instance i:=(0,1), that satisfies i^2+1=0.

So, it seems you are denying the most pure essence about algebraic
concepts.  

Regards.


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Edgar E. Escultura  
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 More options Nov 7, 9:03 am
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Fri, 06 Nov 2009 23:03:52 EST
Local: Sat, Nov 7 2009 9:03 am
Subject: Re: Two fatal defects of Wiles' proof of FLT
Of course, sqrt(-1) has two roots and the reason you choose one of them is to hide the contradiction in it. Your choice, however, does not resolve the fact that sqrt(-1) yields a contradiction. The source of the problem is the vacuous concept i = the root of the equation, x^2 + 1 = 0, among the real numbers which does not exist. Therefore, i is ill-defined, ambiguous, and contradiction usually hides in ambiguity. The full remedy for the complex plane is in the appendix to my paper, The generalized integral as dual of Schwarz distribution, in press, Nonlinear Studies. E. E. Escultua

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Edgar E. Escultura  
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 More options Nov 7, 9:57 am
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Fri, 06 Nov 2009 23:57:48 EST
Local: Sat, Nov 7 2009 9:57 am
Subject: Re: Two fatal defects of Wiles' proof of FLT
Welcome Fernando; hope you are a compatriot.

The bottomline is that the field axioms that supposedly define the real numbers are inconsistent. In particular, the trichotomy and completeness axioms are false. The counterexamples to them are noted elsewhere on this thread and the referecences are cited. Consequently, the real number system is neither complete nor a field nor ordered by "<". In fact, it is ill-defined and all those results you cited fall through.

The objects that satisfy x^2 + 1 = 0 are ill-defined. Hamilton tried to build the complex plane as ordered pairs but he did not identify the right consistent axioms that well define them. The remedy is in the appendix to my paper, The generalized integral as dual of Schwartz distribution, in press, Nonlinear Studies.  

Cheers,

E. E. Escultura


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Edgar E. Escultura  
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 More options Nov 7, 10:25 am
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Sat, 07 Nov 2009 00:25:21 EST
Local: Sat, Nov 7 2009 10:25 am
Subject: Re: Two fatal defects of Wiles' proof of FLT
Correct me if I'm wrong, you can define C to be R[x]/<x^2+1>, the
quotient ring of the set of polynomials with real coefficients modded
out by the ideal generated by x^2+1. The isomorphism sends x to i.
There is nothing ill-defined about that.
----
The fact the the  concepts and spaces you have here are defined in terms of the real number system makes them ill-defined because the latter is, the field axioms that define it being inconsistent. The ideal generated by x^2 + 1 needs to be well defined by a set of consistent axiom.

You can also define C by the set of ordered pairs of real numbers with and multiplication for ordered pairs
of real numbers. Again, nothing ill-defined about that.
-------
Yes, this has been done by Hamilton. But he relied on the real numbers which are ill-defined.

What is really needed here is fix the real number system first which I did in the paper I cited elsewhere on this thread.

Moreover, you seem to be suggesting that since a polynomial equation
has no real roots implies that C is ill-defined. Maybe you can explain
why I'm wrong but that's like saying that since 3x+1=-1 has no roots
among the integers that Q is ill-defined, and like saying that since
x^2 = 2 has no rational roots that the set of irrationals are ill-
defined. There is a progression of number sets that allow for more
polynomial equations to be "solved" (ie, roots found), starting with
N, then Z, Q, R, and finally C. That C is algebraically closed
implies that polynomials will not yield further number sets.

Certainly, the root of a polynomial that has no root is ill-defined, in fact, a contradiction.

What you are suggesting is an extension of the reals that will yield roots to such polynomials. But an extension of any mathematical space belongs to its complement and is not covered by its axioms assuming that they are consisent. Therefore, you need a new set of consistent axioms for them.

Congratulations. You have the most advanced commments so far in contrast to the name callers whose posts come from the flat of their foot because the top is quite empty.

Cheers.

E. E. Escultura


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fernando revilla  
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 More options Nov 7, 11:13 am
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From: fernando revilla <frej0...@ficus.pntic.mec.es>
Date: Sat, 07 Nov 2009 01:13:15 EST
Local: Sat, Nov 7 2009 11:13 am
Subject: Re: Two fatal defects of Wiles' proof of FLT

E.E. Escultura wrote:
> The bottomline is that the field axioms that
> supposedly define the real numbers are inconsistent.

In that case, and from those field axioms you have to provide
a well formed formula A such that A and (~ A) are theorems.

Regards.


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Edgar E. Escultura  
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 More options Nov 7, 1:58 pm
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Sat, 07 Nov 2009 03:58:59 EST
Local: Sat, Nov 7 2009 1:58 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
The counterexamples prove the inconsistency of the field axioms.

Cheers.

E. E. Escultura


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Edgar E. Escultura  
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 More options Nov 7, 1:55 pm
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From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Sat, 07 Nov 2009 03:55:53 EST
Local: Sat, Nov 7 2009 1:55 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
An axiomatic system is completely well defined by the axioms including the rules of inference. Therefore, formal logic does not apply since the axioms have nothing to do with it.

Cheers.

E. E. Escultura


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Brian  
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 More options Nov 8, 12:35 am
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From: Brian <tenn...@gmail.com>
Date: Sat, 7 Nov 2009 11:35:35 -0800 (PST)
Local: Sun, Nov 8 2009 12:35 am
Subject: Re: Two fatal defects of Wiles' proof of FLT
I vaguely recall something about a way to define real numbers as
equivalence classes of sequences of rational numbers where the
equivalence relation between two rational sequences is that two
sequences are considered equivalent if the terms in the sequence get
arbitrarily close to one another (ie, the tails of the two sequences
differ by an arbitrarily small rational number).  For example, the
square root of 2 is defined to be the equivalence class of the
sequence {1, 1.4, 1.41, 1.414, 1.4142, 1.41421, ...}.  The addition
and multiplication of two real numbers (ie, two equivalence classes of
rational sequences) is done by taking the equivalence class of the
sequence whose nth term is the sum or product of the nth term of
representative sequence1 with nth term of representative sequence2.
(The sum and product need to be shown independent of which
representative sequence you use, of course.)  From those definitions,
you can define subtraction and division.

Between that and the Dedekind cut construction of the real numbers,
what is inconsistent?
http://en.wikipedia.org/wiki/Dedekind_cut#The_cut_construction_of_the...

>What is really needed here is fix the real number system first which I did in the paper I cited elsewhere on this thread.

At any rate, you say you've fixed the real number system.  Why can't
the complex numbers be defined as ordered pairs of Escultura-type real
numbers?

>Therefore, formal logic does not apply since the axioms have nothing to do with it.

Please explain!

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fernando revilla  
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 More options Nov 8, 1:37 pm
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From: fernando revilla <frej0...@ficus.pntic.mec.es>
Date: Sun, 08 Nov 2009 03:37:15 EST
Local: Sun, Nov 8 2009 1:37 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT

Brian Tenneson wrote:
> At any rate, you say you've fixed the real number
> system.  Why can't
> the complex numbers be defined as ordered pairs of
> Escultura-type real
> numbers?

Right. I also thought that way.

Regards.


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fernando revilla  
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 More options Nov 8, 2:08 pm
Newsgroups: sci.math
From: fernando revilla <frej0...@ficus.pntic.mec.es>
Date: Sun, 08 Nov 2009 04:08:27 EST
Local: Sun, Nov 8 2009 2:08 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT

E.E. Escultura wrote:
> The counterexamples prove the inconsistency of the
> field axioms.

Well, we need only one. We can analyze it.

Regards.


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Edgar E. Escultura  
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 More options Nov 8, 2:06 pm
Newsgroups: sci.math
From: "Edgar E. Escultura" <escultu...@yahoo.com>
Date: Sun, 08 Nov 2009 04:06:58 EST
Local: Sun, Nov 8 2009 2:06 pm
Subject: Re: Two fatal defects of Wiles' proof of FLT
Brian Tenneson:

I vaguely recall something about a way to define real numbers as
equivalence classes of sequences of rational numbers where the
equivalence relation between two rational sequences is that two
sequences are considered equivalent if the terms in the sequence get
arbitrarily close to one another (ie, the tails of the two sequences
differ by an arbitrarily small rational number). For example, the
square root of 2 is defined to be the equivalence class of the
sequence {1, 1.4, 1.41, 1.414, 1.4142, 1.41421, ...}. The addition
and multiplication of two real numbers (ie, two equivalence classes of
rational sequences) is done by taking the equivalence class of the
sequence whose nth term is the sum or product of the nth term of
representative sequence1 with nth term of representative sequence2.
(The sum and product need to be shown independent of which
representative sequence you use, of course.) From those definitions,
you can define subtraction and division.

Between that and the Dedekind cut construction of the real numbers,
what is inconsistent?
http://en.wikipedia.org/wiki/Dedekind_cut#The_cut_construction_of_the...
----

The Dedekind cut or its equivalent, the completeness axiom of the field axioms of the real numbers do not apply apply to infinite set such as the digits of a nonterminating decimal because ot the latter's ambiguity since not all its digits are known. Any statement about ambiguous set or concept is ambiguous and is not admissible as an axiom for it erodes the validity of any theorme. The other source of inconsistency of the real numbers is the trichotomy axiom to which Brouwer and myself has constructed counterexamples.

>What is really needed here is fix the real number system first which I did in the paper I cited elsewhere on this thread.

At any rate, you say you've fixed the real number system. Why can't
the complex numbers be defined as ordered pairs of Escultura-type real
numbers?
-------

That would be an improvement. However, there must be a reason people do not use this Hamiltonian scheme and resort to the standard notation. Cumbersome, perhaps? At any rate there is simple remedy by looking a i as on operator on the Euclidean plane vectors and e^itheta. This is found in the appendix to my paper, The generalized integral as dual to Schwartz distribution, in press, Nonlinear Studies.

>Therefore, formal logic does not apply since the axioms have nothing to do with it.

Please explain!

Since a mathematical systems is completely well defined solely by its axioms reasoning within it, i.e., the rules of inference must follow from the axioms. In fact, in practice mathematicians do not use formal logic.

Thank you for the most advanced post on this thread so far. E. E. Escultura


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